Two diving platforms 10 m high terminate just at the edge of each end of a swimming pool 30 m long. How fast?

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asked:


Two diving platforms 10 m high terminate just at the edge of each end of a swimming pool 30 m long. How fast must two clowns run straight on their respective platforms if they are to collide midpool, at the surface of the water?

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Komentarze (2) do “Two diving platforms 10 m high terminate just at the edge of each end of a swimming pool 30 m long. How fast?”

  1. Adam Says:

    think of x and y motion separate. first, find how much time it would take for a clown to fall the 10 meters to the water. use this equation- distance= (1/2)at^2. now, each clown would have to fall 15 meters in the x direction to meet in the middle. since during freefall x velocity remains the same, simply divide the distance traveled by time and you have velocity.

    i figured about 1.43 sec for time,

    and about 10.5 m/s for velocity

  2. oldprof Says:

    They will collide when Vx t = X and Vx t = L - X so that 2Vx t = L and Vx = L/2t; where L = 30 m. Vx = ? the speed you’re looking for. t is the time in the air for both clowns; it equals t = sqrt(2H/g); where H = 10 m and g = 9.81 m/sec^2.

    Solve for Vx = L/(2 sqrt(2H/g)) = 30/(2*sqrt(2*10/9.81)) = 10.5 mps ~ 24 mph. ANS.

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